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曾与蒿藜同雨露,한때 잡초와 쑥과 함께 비와 이슬을 나누던 곳이 이제는 소나무와 삼나무와 함께 서리와 눈을 견뎌내고 있다.终随松柏到冰霜.かつては雑草やヨモギと共に雨や露を分かち合っていたが、今では松やヒノキと共に霜や雪に耐えている。曾与蒿藜同雨露,Once sharing rain and dew with weeds and wormwood, now enduring frost and snow with pines and cypresses.终随松柏到冰霜.曾与蒿藜同雨露한때 잡초와 쑥과 함께 비와 이슬을 나누던 곳이 이제는 소나무와 삼나무와 함께 서리와 눈을 견뎌내고 있다.,终随松柏到冰霜.譖セ荳手珍阯懷酔髮ィ髴イ�檎サ磯囂譚セ譟丞芦蜀ー髴�曾与蒿藜同雨露,鏇句笌钂胯棞鍚岄洦闇诧紝缁堥殢鏉炬煆鍒板啺闇�终随松柏到冰霜.曾与蒿藜同雨露,한때 잡초와 쑥과 함께 비와 이슬을 나누던 곳이 이제는 소나무와 삼나무와 함께 서리와 눈을 견뎌내고 있다.终随松柏到冰霜.曾与蒿藜同雨露,终随松柏到冰霜.
"""
``python-future``: pure Python implementation of Python 3 round().
"""
from future.utils import PYPY, PY26, bind_method
# Use the decimal module for simplicity of implementation (and
# hopefully correctness).
from decimal import Decimal, ROUND_HALF_EVEN
def newround(number, ndigits=None):
"""
See Python 3 documentation: uses Banker's Rounding.
Delegates to the __round__ method if for some reason this exists.
If not, rounds a number to a given precision in decimal digits (default
0 digits). This returns an int when called with one argument,
otherwise the same type as the number. ndigits may be negative.
See the test_round method in future/tests/test_builtins.py for
examples.
"""
return_int = False
if ndigits is None:
return_int = True
ndigits = 0
if hasattr(number, '__round__'):
return number.__round__(ndigits)
if ndigits < 0:
raise NotImplementedError('negative ndigits not supported yet')
exponent = Decimal('10') ** (-ndigits)
if PYPY:
# Work around issue #24: round() breaks on PyPy with NumPy's types
if 'numpy' in repr(type(number)):
number = float(number)
if isinstance(number, Decimal):
d = number
else:
if not PY26:
d = Decimal.from_float(number).quantize(exponent,
rounding=ROUND_HALF_EVEN)
else:
d = from_float_26(number).quantize(exponent, rounding=ROUND_HALF_EVEN)
if return_int:
return int(d)
else:
return float(d)
### From Python 2.7's decimal.py. Only needed to support Py2.6:
def from_float_26(f):
"""Converts a float to a decimal number, exactly.
Note that Decimal.from_float(0.1) is not the same as Decimal('0.1').
Since 0.1 is not exactly representable in binary floating point, the
value is stored as the nearest representable value which is
0x1.999999999999ap-4. The exact equivalent of the value in decimal
is 0.1000000000000000055511151231257827021181583404541015625.
>>> Decimal.from_float(0.1)
Decimal('0.1000000000000000055511151231257827021181583404541015625')
>>> Decimal.from_float(float('nan'))
Decimal('NaN')
>>> Decimal.from_float(float('inf'))
Decimal('Infinity')
>>> Decimal.from_float(-float('inf'))
Decimal('-Infinity')
>>> Decimal.from_float(-0.0)
Decimal('-0')
"""
import math as _math
from decimal import _dec_from_triple # only available on Py2.6 and Py2.7 (not 3.3)
if isinstance(f, (int, long)): # handle integer inputs
return Decimal(f)
if _math.isinf(f) or _math.isnan(f): # raises TypeError if not a float
return Decimal(repr(f))
if _math.copysign(1.0, f) == 1.0:
sign = 0
else:
sign = 1
n, d = abs(f).as_integer_ratio()
# int.bit_length() method doesn't exist on Py2.6:
def bit_length(d):
if d != 0:
return len(bin(abs(d))) - 2
else:
return 0
k = bit_length(d) - 1
result = _dec_from_triple(sign, str(n*5**k), -k)
return result
__all__ = ['newround']