shell bypass 403
曾与蒿藜同雨露,한때 잡초와 쑥과 함께 비와 이슬을 나누던 곳이 이제는 소나무와 삼나무와 함께 서리와 눈을 견뎌내고 있다.终随松柏到冰霜.かつては雑草やヨモギと共に雨や露を分かち合っていたが、今では松やヒノキと共に霜や雪に耐えている。曾与蒿藜同雨露,Once sharing rain and dew with weeds and wormwood, now enduring frost and snow with pines and cypresses.终随松柏到冰霜.曾与蒿藜同雨露한때 잡초와 쑥과 함께 비와 이슬을 나누던 곳이 이제는 소나무와 삼나무와 함께 서리와 눈을 견뎌내고 있다.,终随松柏到冰霜.譖セ荳手珍阯懷酔髮ィ髴イ�檎サ磯囂譚セ譟丞芦蜀ー髴�曾与蒿藜同雨露,鏇句笌钂胯棞鍚岄洦闇诧紝缁堥殢鏉炬煆鍒板啺闇�终随松柏到冰霜.曾与蒿藜同雨露,한때 잡초와 쑥과 함께 비와 이슬을 나누던 곳이 이제는 소나무와 삼나무와 함께 서리와 눈을 견뎌내고 있다.终随松柏到冰霜.曾与蒿藜同雨露,终随松柏到冰霜.
# -*- coding: utf-8 -*-
#
# PubKey/RSA/_slowmath.py : Pure Python implementation of the RSA portions of _fastmath
#
# Written in 2008 by Dwayne C. Litzenberger <dlitz@dlitz.net>
#
# ===================================================================
# The contents of this file are dedicated to the public domain. To
# the extent that dedication to the public domain is not available,
# everyone is granted a worldwide, perpetual, royalty-free,
# non-exclusive license to exercise all rights associated with the
# contents of this file for any purpose whatsoever.
# No rights are reserved.
#
# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND,
# EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF
# MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND
# NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS
# BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN
# ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN
# CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
# SOFTWARE.
# ===================================================================
"""Pure Python implementation of the RSA-related portions of Crypto.PublicKey._fastmath."""
__revision__ = "$Id$"
__all__ = ['rsa_construct']
import sys
if sys.version_info[0] == 2 and sys.version_info[1] == 1:
from Crypto.Util.py21compat import *
from Crypto.Util.number import size, inverse, GCD
class error(Exception):
pass
class _RSAKey(object):
def _blind(self, m, r):
# compute r**e * m (mod n)
return m * pow(r, self.e, self.n)
def _unblind(self, m, r):
# compute m / r (mod n)
return inverse(r, self.n) * m % self.n
def _decrypt(self, c):
# compute c**d (mod n)
if not self.has_private():
raise TypeError("No private key")
if (hasattr(self,'p') and hasattr(self,'q') and hasattr(self,'u')):
m1 = pow(c, self.d % (self.p-1), self.p)
m2 = pow(c, self.d % (self.q-1), self.q)
h = m2 - m1
if (h<0):
h = h + self.q
h = h*self.u % self.q
return h*self.p+m1
return pow(c, self.d, self.n)
def _encrypt(self, m):
# compute m**d (mod n)
return pow(m, self.e, self.n)
def _sign(self, m): # alias for _decrypt
if not self.has_private():
raise TypeError("No private key")
return self._decrypt(m)
def _verify(self, m, sig):
return self._encrypt(sig) == m
def has_private(self):
return hasattr(self, 'd')
def size(self):
"""Return the maximum number of bits that can be encrypted"""
return size(self.n) - 1
def rsa_construct(n, e, d=None, p=None, q=None, u=None):
"""Construct an RSAKey object"""
assert isinstance(n, int)
assert isinstance(e, int)
assert isinstance(d, (int, type(None)))
assert isinstance(p, (int, type(None)))
assert isinstance(q, (int, type(None)))
assert isinstance(u, (int, type(None)))
obj = _RSAKey()
obj.n = n
obj.e = e
if d is None:
return obj
obj.d = d
if p is not None and q is not None:
obj.p = p
obj.q = q
else:
# Compute factors p and q from the private exponent d.
# We assume that n has no more than two factors.
# See 8.2.2(i) in Handbook of Applied Cryptography.
ktot = d*e-1
# The quantity d*e-1 is a multiple of phi(n), even,
# and can be represented as t*2^s.
t = ktot
while t%2==0:
t=divmod(t,2)[0]
# Cycle through all multiplicative inverses in Zn.
# The algorithm is non-deterministic, but there is a 50% chance
# any candidate a leads to successful factoring.
# See "Digitalized Signatures and Public Key Functions as Intractable
# as Factorization", M. Rabin, 1979
spotted = 0
a = 2
while not spotted and a<100:
k = t
# Cycle through all values a^{t*2^i}=a^k
while k<ktot:
cand = pow(a,k,n)
# Check if a^k is a non-trivial root of unity (mod n)
if cand!=1 and cand!=(n-1) and pow(cand,2,n)==1:
# We have found a number such that (cand-1)(cand+1)=0 (mod n).
# Either of the terms divides n.
obj.p = GCD(cand+1,n)
spotted = 1
break
k = k*2
# This value was not any good... let's try another!
a = a+2
if not spotted:
raise ValueError("Unable to compute factors p and q from exponent d.")
# Found !
assert ((n % obj.p)==0)
obj.q = divmod(n,obj.p)[0]
if u is not None:
obj.u = u
else:
obj.u = inverse(obj.p, obj.q)
return obj
class _DSAKey(object):
def size(self):
"""Return the maximum number of bits that can be encrypted"""
return size(self.p) - 1
def has_private(self):
return hasattr(self, 'x')
def _sign(self, m, k): # alias for _decrypt
# SECURITY TODO - We _should_ be computing SHA1(m), but we don't because that's the API.
if not self.has_private():
raise TypeError("No private key")
if not (1 < k < self.q):
raise ValueError("k is not between 2 and q-1")
inv_k = inverse(k, self.q) # Compute k**-1 mod q
r = pow(self.g, k, self.p) % self.q # r = (g**k mod p) mod q
s = (inv_k * (m + self.x * r)) % self.q
return (r, s)
def _verify(self, m, r, s):
# SECURITY TODO - We _should_ be computing SHA1(m), but we don't because that's the API.
if not (0 < r < self.q) or not (0 < s < self.q):
return False
w = inverse(s, self.q)
u1 = (m*w) % self.q
u2 = (r*w) % self.q
v = (pow(self.g, u1, self.p) * pow(self.y, u2, self.p) % self.p) % self.q
return v == r
def dsa_construct(y, g, p, q, x=None):
assert isinstance(y, int)
assert isinstance(g, int)
assert isinstance(p, int)
assert isinstance(q, int)
assert isinstance(x, (int, type(None)))
obj = _DSAKey()
obj.y = y
obj.g = g
obj.p = p
obj.q = q
if x is not None: obj.x = x
return obj
# vim:set ts=4 sw=4 sts=4 expandtab: