shell bypass 403
"""
raven.transport.http
~~~~~~~~~~~~~~~~~~~~
:copyright: (c) 2010-2012 by the Sentry Team, see AUTHORS for more details.
:license: BSD, see LICENSE for more details.
"""
from __future__ import absolute_import
from raven.utils.compat import string_types, urllib2
from raven.conf import defaults
from raven.exceptions import APIError, RateLimited
from raven.transport.base import Transport
from raven.utils.http import urlopen
class HTTPTransport(Transport):
scheme = ['sync+http', 'sync+https']
def __init__(self, timeout=defaults.TIMEOUT, verify_ssl=True,
ca_certs=defaults.CA_BUNDLE):
if isinstance(timeout, string_types):
timeout = int(timeout)
if isinstance(verify_ssl, string_types):
verify_ssl = bool(int(verify_ssl))
self.timeout = timeout
self.verify_ssl = verify_ssl
self.ca_certs = ca_certs
def send(self, url, data, headers):
"""
Sends a request to a remote webserver using HTTP POST.
"""
req = urllib2.Request(url, headers=headers)
try:
response = urlopen(
url=req,
data=data,
timeout=self.timeout,
verify_ssl=self.verify_ssl,
ca_certs=self.ca_certs,
)
except urllib2.HTTPError as exc:
msg = exc.headers.get('x-sentry-error')
code = exc.getcode()
if code == 429:
try:
retry_after = int(exc.headers.get('retry-after'))
except (ValueError, TypeError):
retry_after = 0
raise RateLimited(msg, retry_after)
elif msg:
raise APIError(msg, code)
else:
raise
return response